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34x=(12x^2)-6
We move all terms to the left:
34x-((12x^2)-6)=0
We get rid of parentheses
-12x^2+34x+6=0
a = -12; b = 34; c = +6;
Δ = b2-4ac
Δ = 342-4·(-12)·6
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-38}{2*-12}=\frac{-72}{-24} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+38}{2*-12}=\frac{4}{-24} =-1/6 $
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